最新 2025 Oracle 1Z0-809 認證問題和模擬測試，Java SE 8 程序員 II | SPOTO

給定代碼片段： class CallerThread implements Callable { String str; public CallerThread(String s) {this.str=s;} public String call() throws Exception { return str.concat("Call"); } and public static void main (String[] args throw InterruptedException; ExecutionException { ExecutorService es = Executors.newFixedThreadPool(4); } 和} and public static void main (String[] args) throws InterruptedException, ExecutionException { ExecutorService es = Executors.newFixedThreadPool(4); //line n1 Future f1 = es.submit (newCallerThread("Call")); String str = f1.get().toString(); System.out.println(str); } }.哪條語句是正確的？

給出：和代碼片段：ColorSorter 類的哪個定義會對色塊列表進行排序？

給出代碼片段：List colors = Arrays.asList("red", "green", "yellow"); Predicate test = n - > { System.out.println("Searching..."); return n.contains("red"); }; colors.stream() .f ilter(c -> c.length() > 3) .allMatch(test); 結果如何？

給定：Book.java: public class Book { private String read(String bname) { return "Read" + bname }}EBook.java: public class EBook extends Book { public class String read (String url) { return "View" + url }}Test.java: public class Test { public static void main (String[] args) { Book b1 = new Book(); b1.read("Java Programing"); Book b2 = new EBook(); b2.read("http://ebook.com/ebook"); } }}結果如何？

鑑於可以訪問 course.txt，其中包含Course : ：Java 代碼片段： public static void main (String[ ] args) { int i; char c; try (FileInputStream fis = new FileInputStream ("course.txt"); InputStreamReader isr = new InputStreamReader(fis);){ while (isr.ready()) { //line n1 isr.skip(2); i = isr.read (); c = (char) i; System.out.print(c); }} catch (Exception e) { e.printStackTrace(); }}結果如何？

給出代碼片段：UnaryOperator uo1 = s -> s*2; line n1 List loanValues = Arrays.asList(1000.0, 2000.0); loanValues.stream() .filter(lv -> lv >= 1500) .map(lv -> uo1.apply(lv)) .forEach(s -> System.out.print(s + " ")); 結果如何？

給出： 和代碼片段：結果是什麼？

給出：和這個代碼片段：結果是什麼？

給出代碼片段： class Caller implements Callable { String str; public Caller (String s) {this.str=s;} public String call()throws Exception { return str.concat ("Caller");} } class Runner implements Runnable { String str; public Runner (String s) {this.str=s;} public void run (){ System.out.printn (str.concat ("Caller");}class Runner implements Runnable { String str; public Runner (String s) {this.str=s;} public void run () { System.out.println (str.concat ("Runner"));}} and public static void main (String[] args) InterruptedException, ExecutionException { ExecutorService es = Executors.newFixedThreadPool(2); Future f1 = es.submit (ne).

結果如何？

鑑於可以訪問 data.txt 和 alldata.txt，以及代碼片段：要使代碼能用 data.txt 覆蓋 alldata.txt，第 n1 行需要做些什麼？